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#101 Nov 30, 2013 5:19 AM

36IStillLikeSpyro36
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Re: Let's Count 2.0

11


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#102 Nov 30, 2013 5:21 AM

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Re: Let's Count 2.0

12

FANMADE_YEAH!!!.gif


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#103 Nov 30, 2013 5:32 AM

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Re: Let's Count 2.0

13


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#104 Nov 30, 2013 7:42 AM

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Re: Let's Count 2.0

15


2i0zslx_th.jpg8x0xaf_th.jpgdrf14y_th.jpg25euwjd_th.jpg2rwakus_th.jpgo85htj_th.jpg

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#105 Nov 30, 2013 8:21 AM

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Re: Let's Count 2.0

NOOOOOOOOOOOO 1


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#106 Nov 30, 2013 1:17 PM

Clock-la
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Re: Let's Count 2.0

STOP YOU TWITS!!!!!!!!


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#107 Nov 30, 2013 9:55 PM

Hwd45
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Re: Let's Count 2.0

∫(1/x)dx, 0≤x≤e


8alc.pngd6hu.png

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#108 Dec 01, 2013 3:36 AM

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Re: Let's Count 2.0

1. are you quite happy with yourselves?


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#109 Dec 01, 2013 3:43 AM

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Re: Let's Count 2.0

2. NO


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#110 Dec 01, 2013 11:11 AM

Clock-la
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Re: Let's Count 2.0

I am


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#111 Dec 01, 2013 12:25 PM

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Re: Let's Count 2.0

Yup

Hwd45 wrote:

∫(1/x)dx, 0≤x≤e

ln(x) + c

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#112 Dec 01, 2013 12:56 PM

Clock-la
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Re: Let's Count 2.0

343333


Welcome to Nya Nya Nya please just call me Tatsumina no Mikoto Cocona! NYAMO!!
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#113 Dec 01, 2013 7:48 PM

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Re: Let's Count 2.0

1


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#114 Dec 01, 2013 8:08 PM

Swaffy
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Re: Let's Count 2.0

Two


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#115 Dec 01, 2013 11:16 PM

Clock-la
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Re: Let's Count 2.0

gay penguins.


Welcome to Nya Nya Nya please just call me Tatsumina no Mikoto Cocona! NYAMO!!
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#116 Dec 02, 2013 6:07 AM

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Re: Let's Count 2.0

1


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#117 Dec 02, 2013 7:00 AM

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Re: Let's Count 2.0

2 male penguins in a platonic frienship.

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#118 Dec 02, 2013 7:10 AM

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Re: Let's Count 2.0

3


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#119 Dec 02, 2013 4:31 PM

Swaffy
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Re: Let's Count 2.0

4 ... again again again.


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#120 Dec 02, 2013 6:05 PM

Clock-la
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Re: Let's Count 2.0

Stormy wrote:

2 male penguins in a platonic frienship.

You mean FINship!


Welcome to Nya Nya Nya please just call me Tatsumina no Mikoto Cocona! NYAMO!!
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#121 Dec 02, 2013 10:04 PM

Hwd45
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Re: Let's Count 2.0

Gekoncze wrote:

Yup

Hwd45 wrote:

∫(1/x)dx, 0≤x≤e

ln(x) + c

since I couldn't write the limits on the integral I wrote them as 0≤x≤e, but I actually meant 1≤x≤e. If I had written this correctly, ∫(1/x)dx = ln(e)-ln(1) = 1-0 = 1


8alc.pngd6hu.png

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#122 Dec 02, 2013 10:43 PM

Swaffy
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Re: Let's Count 2.0

Schfffffaive.


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#123 Dec 03, 2013 2:22 AM

36IStillLikeSpyro36
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Re: Let's Count 2.0

1.


Dіsсоrd - 7Arterial7Justice7 [[HASHTAG]] 6565
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#124 Dec 03, 2013 7:23 PM

Clock-la
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Re: Let's Count 2.0

22


Welcome to Nya Nya Nya please just call me Tatsumina no Mikoto Cocona! NYAMO!!
r03z14.jpg
Oh the indignity.

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#125 Dec 03, 2013 8:56 PM

Gekoncze
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Re: Let's Count 2.0

Hwd45 wrote:
Gekoncze wrote:

Yup

Hwd45 wrote:

∫(1/x)dx, 0≤x≤e

ln(x) + c

since I couldn't write the limits on the integral I wrote them as 0≤x≤e, but I actually meant 1≤x≤e. If I had written this correctly, ∫(1/x)dx = ln(e)-ln(1) = 1-0 = 1

ah :3

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